ABCD is a square of side length 1 unit.P and Q are points on AB and BC such that `/_PDQ=45^(@)` .Then the perimeter of `Delta PBQ` is

Area of square ABCD is 4 unit^2 *M and N are mid points of AB and BC. Find PC.

Let ABCD is a square with sides of unit length. Points E and F are taken om sides AB and AD respectively so that AE=AF .Let P be a point inside the square ABCD.The maximum possible area of quadrilateral CDFE is-

DeltaABC is an equilateral triangle, AB = 6. The points P, Q and Rare midpoints of AB, BC and CA respectively. The perimeter of PBCR is

In the figure,ABCD is a square of side 1dm and /_PAQ=45^(@). The perimeter ( in dm) of the triangle PQC is

ABCD is rectangle.P and Q are points on AB and BC respectively such that the area of triangle APD=5, area of triangle PBQ=4 and area of triangle QCD=3, all areas in square units.Then the areaof the triangle DPQ in square units is

Consider a square OABC ,If P and Q are the midpoints of sides AB and BC ,respectively. Then the value of (2(Area of Delta OPQ))/(Area of square OABC) is

19.ABCD is a rectangle having length (x1) and breadth (x-1). If P,Q,R and S are the mid- points of sides AB,BC,CD and DA respectively,then the perimeter of quadrilateral PQRS is

A circle touches the side BC of a Delta ABC at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of Delta ABC = 26.4 cm, then the length of AQ is: