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Let matrix A=[[1,0,0],[1,0,1],[0,1,0]] t...

Let matrix `A=[[1,0,0],[1,0,1],[0,1,0]]` then the value of `|A^(2012)-I|` is equal to

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Let A = [[1,0,0],[1,0,1], [0,1,0]] " satisfies " A^(n) = A^(n-2) + A^(2 ) -I for nge 3 and consider matrix underset(3xx3)(U) with its columns as U_(1), U_(2), U_(3), such that A^(50)U_(1)=[[1],[25],[25]],A^(50) U_(2)=[[0],[1],[0]]and A^(50) U_(3)[[0],[0],[1]] The value of abs(A^(50)) equals

Let A = [[1,0,0],[1,0,1], [0,1,0]] " satisfies " A^(n) = A^(n-2) + A^(2 ) -I for nge 3 and consider matrix underset(3xx3)(U) with its columns as U_(1), U_(2), U_(3), such that A^(50)U_(1)=[[1],[25],[25]],A^(50) U_(2)=[[0],[1],[0]]and A^(50) U_(3)[[0],[0],[1]] The value of abs(U) equals

Let A = [[1,0,0],[1,0,1], [0,1,0]] " satisfies " A^(n) = A^(n-2) + A^(2 ) -I for nge 3 and consider matrix underset(3xx3)(U) with its columns as U_(1), U_(2), U_(3), such that A^(50)U_(1)=[[1],[25],[25]],A^(50) U_(2)=[[0],[1],[0]]and A^(50) U_(3)[[0],[0],[1]] Trace of A^(50) equals