A particle is moving in a circular path. The acceleration and moment of the particle at a certain moment are `a=(4 hat(i)+3hat(j))m//s^(2) and p=(8 hat(i)-6hat(j))"kg-m/s"`. The motion of the particle is

A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are a=(4 hat(i)+3hat(j))m//s^(2) and p=(8 hat(i)-6hat(j))"kg-m/s" . The motion of the particle is

Velocity and acceleration of a particle at time t = 0 are u=(2hat(i)+3hat(j))m//s and a=(4hat(i)+2hat(j))m//s^(2) respectively. Find the velocity and displacement of particle at t = 2 s.

At a particular instant velocity and acceleration of a particle are (-hat(i)+hat(j)+2hat(k))m//s and (3hat(i)-hat(j)+hat(k))m//s^(2) respectively at the given instant particle's speed is :

A particle velocity changes from (2hat(i)+3hat(j))ms^(-1) to (2hat(i)-3hat(j))ms^(-1) in 2 s. The acceleration in ms^(-2) is

A particle moves in x-y plane according to the equation bar(r ) = (hat(i) + 2 hat(j)) A cos omega t the motion of the particle is

A particle is moving in xy-plane in a circular path with centre at origin. If at an instant the position of particle is given by (1)/(sqrt(2)) ( hat(i) + hat(j)) , then velocity of particle is along

A particle is moving with a constant acceleration vec(a) = hat(i) - 2 hat(j) m//s^(2) and instantaneous velocity vec(v) = hat(i) + 2 hat(j) + 2 hat(k) m//s then rate of change of speed of particle 1 second after this instant will be :

A particle is moving in xy -plane in circular path with centre at origin.If at an instant the position of particle is given by (1)/(sqrt(2))(hat i+hat j) .Then velocity of particle is along (A) (1)/(sqrt(2))(hat i-hat j) (B) (1)/(sqrt(2))(hat j-hat i) (C) (1)/(sqrt(2))(hat i+hat j) (D) Either (A) or (B)