If A is a square matrix of order `nxxn` and k is a scalar, then `adj(kA)=`

If A is a square matrix of order n xx n and k is a scalar, then adj (kA) is equal to (1) k adj A (2) k^n adj A (3) k^(n-1) adj A (4) k^(n+1) adj A

If A is a square matrix of order n xx n and k is a scalar, then adj (kA) is equal to (1) k adj A (2) k^n adj A (3) k^(n-1) adj A (4) k^(n+1) adj A

If A is a square matrix of order n xx n and k is a scalar, then adj (kA) is equal to (1) k adj A (2) k^n adj A (3) k^(n-1) adj A (4) k^(n+1) adj A

If A=[a_(ij)] is a square matrix of order nxxn and k is a scalar then |kA|=

If A=[a_(ij)] is a scalar matrix of order nxxn and k is a scalar, then abs(kA)=

If A is a square matrix of order nxxn and lamda is a scalar then |lamdaA| is (A) lamda|A| (B) lamda^n|A| (C) |lamda||A| (D) none of these

If A is a square matrix of order nxxn and lamda is a scalar then |lamdaA| is (A) lamda|A| (B) lamda^n|A| (C) |lamda||A| (D) none of these

If A is a square matrix of order 3xx3 and lambda is a scalar, then adj (lambdaA) is equal to -

If A is a square matrix of order n then |kA|=