A particle executing a SHM has maximum acceleration at a distance of 0.5 cm from its mean position is `2cm//s^(2)` . What will be its velocity when it is at a distance of 1 cm from its mean position.

A particle executing SHM has amplitude of 4cm, and its acceleration at a distance of 1cm from the mean position is 3cm^(-2) . What will its velocity be when it is at a distance of 2 cm from its mean position?

If particle executing S.H.M. has an amplitude of 6 cm, its acceleration at a distance 2 cm from mean position is 8 cm/s^2 , then the maximum speed of the particle will be

The acceleration of a particle executing SHM at a distance of 3 cm from equilibrium position is 5 cm//s^(2) . Its acceleration at a distance of 2 cm from equilibrium position is

The speed of a particle executing SHM with amplitude of displacement 5 cm is 3 cm //s at a distance 2.5 cm from mean position. What will be its speed at a distance 2.5 sqrt(3) from mean position?

The speed of a particle executing SHM with amplitude of displacement 5 cm is 3 cm //s at a distance 2.5 cm from mean position. What will be its speed at a distance 2.5 sqrt(3) from mean position?