The rate of increases of bacteria in a certain culture is proportional to the number present. If it doubles in `5` hr., then in `25` hr., its number would be

The rate of increase of bacteria in a certain culture is proportional to the number present . If it doubles in 5 hours , then in 25 hours , its number would be

The rate of increase of bacterial in a certain culture is proportional to the number of bacterial present. If it is found that the number doubled in 5 hours, prove that the bacterial becomes eight times at the end of 15 hours.

The rate of increase in the number of bacteria in a certain bacteria culture is proportional to the number present. If in 5 hrs the number triples, then in 10 hrs, the number of bacteria present is

The rate of increase in the number of bacteria in a certain bacteria culture is proportional to the number present. Given the number triples in 5 hrs., find how many bacteria will be present after 10 hours. Also find the time necessary for the number of bacteria to be 10 times the number of initial present. [Given log_e3=1. 0986 , e^(2. 1972)=9 ]

The rate of increase in the number of bacteria in a certain bacteria culture is proportional to the number present. Given the number triples in 5 hrs., find how many bacteria will be present after 10 hours. Also find the time necessary for the number of bacteria to be 10 times the number of initial present. [Given log_e3=1. 0986 ,\ e^(2. 1972)=9 ]

The rate of increase in the number of bacteria in a certain bacteria culture is proportional to the number present. Given that the number triples in 5 hours, find how many bacteria will be present after 10 hours ?