An electron beam can undergo defraction by crystals .Through what potential should a beam of electrons beb acceleration so that its wavelength becomkes equal to `1.54 Å`

An electron beam can undergo defractio by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.45Å .

An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength is equal to 1.6 A?

An electron beam can undergo diffraction by crystals. The potential of 'V' volt should a beam of electrons be accelerated so that its wavelength becomes equal to 1.0Å . The value of 'V' is Given: (h^(2))/(m_(e)xxe)=3xx10^(-18)J^(2)s^(2)kg^(-1)"coulomb"^(-1)

An electron beam can undergo diffraction by crystals. The potential of 'V' volt should a beam of electrons be accelerated so that its wavelength becomes equal to 1.0Å . The value of 'V' is Given: (h^(2))/(m_(e)xxe)=3xx10^(-18)J^(2)s^(2)kg^(-1)"coulomb"^(-1)

Through what potential difference should an electron be accelerated so that its de-Broglie wavelength becomes 0.4Å?