Motion of a particle is given by equation `S = (3t^(3) + 7 t^(2) + 14 + t + 8)`m, The value of acceleration of the particle at t = 1 sec, is:

Motion of particle is given by equation s=(3t^(3)+7t^(2)+14t+8)m The value of acceleration of the particle at t = 1 s is

Motion of particle is given by equation s=(5t^(3)+3t^(2)+8t+17)m The value of acceleration of the particle at t = 2 s is

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then,the angular acceleration of the particle at t=2 sec is ……. rad s^(-2)

If the motion of aparticle is governed by the equation, s= 2t^3- 3t^2+ 2t +2 , find the poswition, velocity and acceleration of the particle at time t=2s .

The x and y co-ordinates of a particle at any time t are given as x = 2t^2 +14 and y = 1.5t - 7 . The acceleration of particle at t = 7 sec is :

The displacement of a particle in time 't' is given by S = t^(3) - t^(2) - 8t =18 . The acceleration of the particle when its velocity vanishes is

The displacement of particle with respect to time is s = 3^(t3) - 7t^(2) + 5t + 8 where s is in m and t is in s, then acceleration of particle at t = ls is

The displacement of a particle is represented by following equation: s=3t^(3) +7t^(2) +5t +8 where is in metre and in second the acceleration of particle at s is