A force `vec(F) = 5hati + 4hatj` newton displaces a body through `vec(S) = 3hati +4 hatk` metre in 3s. Find the power.

A force F = 2hati + 4hatj Newton displaces the body by s = 3hatj + 5hatk meter in 2s. The power generated will be

A force F = 2hati + 4hatj Newton displaces the body by s = 3hatj + 5hatk meter in 2s. The power generated will be

A force vec F=(2hati+2hatk) N displaces a body by an amount vec S=(2hati+2hatj) m in 8 s. What is the power developed ?

When a force (8hati+4hatj) newton displaces a particle through (3hati-3hatj) metre, the power is 0.6W. The time of action of the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force vec(F) = 4 hati + hatj + 3hatk newton acts on a particle and displaces it through displacement vec(S) = 11 hati + 11 hatj +15 hatj metre. Calculate the work done by the force.

A force vecF=(2hati+3hatj+4hatk)N displaces a body from position vector vec(r_(1))=(2hati+3hatj+hatk)m to the positive vector vec(r_(2))=(hati+hatj+hatk)m . Find the work done by this force.