If `I_(1)`,`I_(2)` ,and `I_(3)` are moments of inertia of a disc about its geometric axis,diameter and a tangent in its plane,then

Calculate the moment of inertia of a disc about its any diameter ?

Moment of inertia of a disc about its own axis is I. Its moment of inertia about a tangential axis in its plane is

The moment of inertia of a ring about its geometrical axis is I, then its moment of inertia about its diameter will be

The moment of inertia of a disc of mass M and radius R about a tangent to its rim in its plane is

Moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is frac (1)(2)MR^2 . Determine the moment of inertia of this disc about its diameter and about a tangent perpendicular to its plane.

The Moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is 1 / 2 MR^2 . Derive the values of moment of inertia of the disc about its diameter and about an axis tangential to the disc lying on its plane ?

Assuming he expression for the moment of inertia of a thin disc about its diameter, show that the moment of inertia of the disc about a tangent in its plane is (5)/(4)MR^(2)

The moment of inertia of thin square plate ABCD of uniform thickness about an axis passing through the center O and perpendicular to the plane of the plate is ( i ) I_(1)+I_(2) ( ii ) I_(2)+I_(4) ( iii ) I_(1)+I_(3) ( iv ) I_(1)+I_(2)+I_(3)+I_(4) where I_(1) , I_(2) , I_(3) and I_(4) are repectively moments of inertia about axes 1 , 2 , 3 and 4 which are in the plane of the plane

The moment of inertia of a then circular disc about an axis passing through its centre and perpendicular to its plane is I . Then, the moment of inertia of the disc about an axis parallel to its diameter and touching the edge of the rim is