Home
Class 12
PHYSICS
In a photo-emissive cell, with exciting ...

In a photo-emissive cell, with exciting wavelength `lambda`, the maximum kinetic energy of electron is K. If the exciting wavelength is changed to `( 3 lambda)/( 4)` the kinetic energy of the fastest emitted electron will be `:`

Promotional Banner

Similar Questions

Explore conceptually related problems

In a photo-emissive cell, with exciting wavelength lambda_1 , the maximum kinetic energy of electron is K. If the exciting wavelength is changed to lambda_2 , the maximum kinetic energy of electron is 2K then

In a photoemissive cell, with exciting wavelength lambda , the faster electron has speed v. If the exciting wavelength is changed to 3lambda//4 , the speed of the fastest electron will be

In a photoelectric experiment, with light of wavelength lambda , the fastest election has speed v. If the exciting wavelength is changed to (3lambda)/4 , the speed of the fastest emitted electron will become

In a photoelectric experiment, with light of wavelength lamda , the fastest electron has speed v. If the exciting wavelength is changed to 5lamda/4 , the speed of the fastest emitted electron will become

If the kinetic energy of a electron , it's debroglie wavelength changes by the factor

The kinetic energy of an electron with de - Broglie wavelength of 0.3 nanometre is

An electron and proton have the same de-Broglie wavelength. Then the kinetic energy of the electron is