A magnetising field of `1600 Am^(-1)` produces a magnetic flux `2.4 xx 10^(-5)` weber in an iron bar of cross-sectional area `0.2 cm^(2)` . The susceptibility of the iron bar will be

If a magnetising field of 1600 A//m produces a magnetic flux of 14xx10^(-5) Wb in an iron bar of cross-sectional area 0.2 cm^(2) . Then,

A magneting field of 1600 Am^(-1) produces a magnetic flux of 2.4xx10^(-5) wb in an iron bar of cross-sectional area 0.2cm^(2) .Calculate the permeability and susceptibility of the bar.

A magnetising field fo 1000 A/m produces a magnetics flux of 2.4 xx10^(-5) Wb in an iron bar of cross sectional area 0.3 cm^(2) what is the magnetic permeability of the iron bar ?

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 xx 10^(-5)Wb in a bar of iron of cross section 0.2"cm"^(2) . Then permeability of the bar is the equator

A magnetic field of 1600Am^-1 produces a magnetic flux of 2*4xx10^-5 weber in a bar of iron of cross section 0*2cm^2 . Calculate permeability and susceptibility of the bar.

A magnetising field produces a magnetic flux of 2.2 xx 10^(-5) weber in an iron bar of cross section 0.5 cm^(2) what is the magnetic iduction ?

A magnetising field produces a magnetic flux of 2.2xx10^(-5) weber in an iron bar of cross section 0.5 cm^(2) . What is the magnetic induction?

A magnetising field of 1500 A//m produces a flux of 2*4xx10^-5 weber in a bar of iron of cross-sectional area 0*5cm^2 . Calculate the permeability and susceptibility of the iron bar used.

A magnetising field of 5000 A/m produces a magnetic flux of 5xx10^(-5) weber in an iron rod. If the area of cross section of the rod is 0.5cm^(2) , then the permeability of the rod will be