Cu+y`HNO_(3)``rarr` `Cu(NO_(3))_(2)`+Z`NO`+`H_(2)O`.Then y" and "z" in the balanced chemical equation are respectively "

3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O the wrong statement for the value

a Cr_(2)O_(7)^(2-) + b H^(+) + cS^(2-) rarr x Cr^(3+) + yS + zH_(2)O The value of a, b, c, x, y and z in the balanced chemical reaction are :

Cu+X rarr Cu(NO_(3))_(2) + 2H_(2)O + 2NO_(2) . Here X is -

A mixture of Cu_2O and Cu_2S is heated. Write a balanced chemical equation.

\(x Zn+y HNO_{3}\rightarrow Zn(NO_{3})_{2}+NH_{4}NO_{3}+H_{2}O\). In the balanced equation "x" and "y" are

\(x Zn+y HNO_{3}\rightarrow Zn(NO_{3})_{2}+NH_{4}NO_{3}+H_{2}O\). In the balanced equation "x" and "y" are

Cu reacts with HNO_(3) according to the equation Cu+HNO_(3)rarrCu(NO_(3))_(2)+NO_(2)+H_(2)O If NO and NO_(2) are formed in a 2:3 ratio, what is the coefficient for Cu when the equation is balanced with the simplest whole numbers ?

The equation Cu + XHNO_(3) to Cu(NO_(3)) + Y NO_(2) + 2H_(2)O the values of X and Y are