A straight line L passing through the point `P(-2,-3)` cuts the lines, `x + 3y = 9` and `x+y+1=0` at Q and R respectively. If `(PQ) (PR) = 20` then the slope line L can be
(A) 4
(B) 1
(C) 2
(D) 3

A straight line through the point A (-2,-3) cuts the line x+3y=9 and x+y+1=0 at B and C respectively. If AB.AC =20 then equation of the possible line is

A straight line through the point A(-2, -3) cuts the line x+3y=9 and x+y+1=0 at B and C respectively. Find the equation of the line if AB.AC = 20 .

Two straight lines passing through the point A(3, 2) cut the line 2y=x+3 and x-axis perpendicularly at P and Q respectively. The equation of the line PQ is

A straight line through the origin o meets the parallel lines 4x+2y= 9 and 2x +y+ 6=0 points P and Q respectively. Then the point o divides the segment PQ in the ratio: : (A) 1:2 (B) 3:2 (C) 2:1 D) 4:3

A straight line through the point A(1,1) meets the parallel lines 4x+2y=9&2x+y+6=0 at points P and Q respectively.Then the point A divides the segment PQ in the ratio:

A straight line through the origin 'O' meets the parallel lines 4x+2y=9 and 2x+y=-6 at points P and Q respectively.Then the point 'divides the segment PQ in the ratio

The equation of the straight line passing through the point (4,3) with slope 2 is 2x-y-5=0 .