The slope of the line passing through the points `(2,sin theta),(1,cos theta)`, is 0 then the general solution of `theta`

If sin3 theta=sin theta, then general solution is

If sin3 theta=sin theta, then general solution is

If sin^(2)theta-2cos theta+(1)/(4)=0 ,then the general value of theta is

If sin theta+cos theta=1, then find the general value of theta.

Find the general solution of cos^2theta(sin^2theta)=1

The slope of the normal to the curve x=a(theta-sin theta),y=a(1-cos theta) at theta=(pi)/(2)

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

The equation to the straight line passing through the point (a "cos"^(3) theta, a "sin"^(3) theta) and perpendicular to the line x "sec" theta + y"cosec" theta = a is

The equation of the locus of the point of intersection of the straight lines x sin theta+(1-cos theta)y=a sin theta and x sin theta-(1-cos theta)y+a sin theta=0 is