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If 3a+2b+c=0 the family of straight line...

If `3a+2b+c=0` the family of straight lines `ax+by+c=0` passes through the fixed point `(p, q)` then `p + q`

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Statement -1 : If a,b,c are parameters such that 3a + 2b+4c=0, then the family of lines ax +by+ c =0 pass through a fixed point (3,2). and Statement -2: The equation ax + by + c =0 wil represent a family of straight lines passing through a fixed point if there exist a linear relation between a, b and c.

(1) if a+b+c=0 the straight line 2ax+3by+4c=0 passes through the fixed point (2) if 3a+2b+4c=0 the straight line ax+by+c=0 passes through the fixed point

If a + 2b + 3c = 0 " then " a/3+(2b)/3+c=0 and comparing with line ax + by + c, we get x = 1/3 & y = 2/ 3 so there will be a point (1/3,2/3) from where each of the lines of the form ax + by + c = 0 will pass for the given relation between a,b,c . We can say if there exists a linear relation between a,b,c then the family of straight lines of the form of ax + by +c pass through a fixed point . If a , b, c are in H.P . then the line acx + bcy + ab = 0 passes through,