Home
Class 11
PHYSICS
A pendulum clock consists of na iron rod...

A pendulum clock consists of na iron rod connected toa small, heavy bob. If it is desisgned to keep correct time at `20^(0) C`, how fast or slow will it go in 24 hours at `40^(0) C?` Coefficient o f inear expanision of iron `= 1.2 xx 10^(-5) ^0 C^(-6).

Promotional Banner

Similar Questions

Explore conceptually related problems

A pendulum clock consists of an iron rod connected to a small, heavy bob. If it is designed to keep correct time at 20^(0) C , how fast or slow will it go in 24 hours at 40^(0) C? Coefficient of linear expansion of iron = 1.2 xx 10^(-5) ^0 C^(-6) .

A pendulum clock consists of an iron rod connected to a small, heavy bob. If it is designed to keep correct time at 20^(0) C , how fast or slow will it go in 24 hours at 40^(0) C? Coefficient of linear expansion of iron = 1.2 xx 10^(-5)C^(-1) .

A pendulum clock consists of an iron rod connected to a small, heavy bob. If it is designed to keep correct time at 20^(0) C , how fast or slow will it go in 24 hours at 40^(0) C? Coefficient of linear expansion of iron = 1.2 xx 10^(-5)C^(-1) .

(a) A pendulum clock consists of an iron rod connected to a small, heavy bob. If it is designed to keep correct time at 20^(@)C , how fast or slow will it go in 24 hours at 50^(@)C ? alpha_(iron)=1.2xx10^(-5)//^(@)C . (b) A pendulum clock having copper rod keeps correct time at 20^(@)C . It gains 15 seconds per day if cooled to 0^(@)C . Find the coefficient the of linear expansion of copper.

A penduluin clock of an iron rod is connected to a small, heavy bob. If it shows correct time at 20^(@)C , how fast or slow will it go in one day at 40^(@)C ? (Coefficient of linear expansion for steel is 12xx10^(-6)//""^(@)C .)

A pendulum clock gives correct time at 20^C at a place where g =9.800 m s^(-2) .The pendulum consists of a light steel rod connected to a heavy ball. It is taken to a different place where g =9.788 m s^(2) . At what temperature will it give correct time ? coefficient of linear expansion of steel = 12 xx 10^(-6) 0^C(-1) .

A pendulum clock gives correct time at 20^@C at a place where g=9.800 m s^(-2) .The pendulum consists of a light steel rod connected to a heavy ball. It is taken to a different place where g=9.788 m s^(-2) . At what temperature will it give correct time ? coefficient of linear expansion of steel = 12 xx 10^(-6)C^(-1) .

A pendulum clock gives correct time at 20^@C at a place where g=9.800 m s^(-2) .The pendulum consists of a light steel rod connected to a heavy ball. It is taken to a different place where g=9.788 m s^(-2) . At what temperature will it give correct time ? coefficient of linear expansion of steel = 12 xx 10^(-6)C^(-1) .

A clock with an iron pendulum keeps correct time at 20^@C . How much will it lose are gain if temperature changes to 40^@C ? (Coefficient of cubical exexpansion of iron = 36 xx 10^(-6) per^@C .)