The mean free path of a gas molecule at `27^(@)C` is 2 cm. If the rms velocity of the gas at that temperature is `10m//s`, what is the time interval between two successive collisions?

Mean free path of a gas molecule is

Mean free path of a gas molecule is :

The mean free path of oxygen gas molecules at STP is 9.5 times 10^-6 cm What is the time interval between two successive collisions of a molecule? Atomic weight of oxygen=32 and R=8.3 times 10^7 erg.mol^-1.K^-1

The mean free path of nitrogen molecules at 27^(@)C is 3xx10^(-7)m//s . If the average speed of nitrogen molecules at the same temperature is 600 m/s then the collision frequency will be

Temperature of an ideal gas initially at 27^@C is raised by 6^@C , The rms velocity of the gas molecule will

An ideal gas is enclosed in a cylinder at pressure of 2atm and temperature, 300K. The mean time between two successive collisions is 6xx10^(-8) s. If the pressure is doubled and temperature is increased to 500K, the mean time between two successive collisions will be close to: