Let `A=[(cos theta, -sin theta),(- sin theta,-cos theta)]` then the inverse of a is

cos theta/(1+sin theta)=(1-sin theta)/cos theta

A = [(cos theta,-sin theta),(-sin theta,-cos theta)] then find A^(-1) .

Verify that [(cos theta, sin theta),(-sin theta, cos theta)] and [(cos theta, - sin theta),(sin theta, cos theta)] are inverse of each other.

Let A = [ (cos theta, sin theta),(- sin theta, cos theta)] , then show that A ^(2) = [(cos 2 theta, sin 2 theta),( - sin 2 theta, cos 2 theta)]

If A=[{:(cos theta, sin theta),(-sin theta, cos theta):}] then "A A"^(T) is :

The inverse of A=[( cos theta, sin theta),(-sin theta, cos theta)] is

The multiplicative inverse of : A = [(cos theta , -sin theta ),(sin theta , cos theta )] is :