AOB is a diameter of a circle with centre O and C is any point on the circle, joining A, C, B, C, and O, C, prove that
`tanangleABC=cotangleACO`

AOB is a diameter of a circle with centre O and C is any point on the circle, joining A, C, B, C, and O, C, prove that sin^(2)angleBCO+sin^(2)angleACO=1

AOB is a diameter of a circle with centre O and C is any point on the circle, joining A, C, B, C, and O, C, prove that cosec^(2)angleCAB-1=tan^(2)angleABC .

AB is a diameter of a circle with centre at O. C is any point on the circle. If angleBOC = 110^@ , then angleBAC =

If AOB is a diameter of a circle and C is a point on the circle, then AC^(2)+BC^(2)=AB^(2) .

If AOB is a diameter of a circle and C is a point on the circle, then AC^(2)+BC^(2)=AB^(2) .

AOB is diameter of a circle whose centre is O and C is any point on the circle. Join A and C , B and C and O and C. Show that (sin^2 /_BCO + sin^2 /_ACO) = 1 .

AB is a diameter of a circle. C is any point on the circle, angleACB=

AB is a diameter of a circle and C is any point on the circumference of the circle, then :

AB is a diameter of a circle and 'C' is any point on the circumference of the circle .Then