Velocity and acceleration of a particle are `v=(2 hati) m/s` and `a = (4t hati+t^2 hatj) m /s^2` where, t is the time. Which type of motion is this ?

Velocity and acceleration of a particle are v=(2 hati-4 hatj) m/s and a=(-2 hati+4 hatj) m/s^2 Which type of motion is this?

Velocity and acceleration of a particle are v=(2 hati-4 hatj) m/s and a=(-2 hati+4 hatj) m/s^2 Which type of motion is this?

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Velocity and acceleration of a particle at time t=0 are vecu =(2hati + 3hatj)m//s s and a = (4hati +2hatj) m//s^(2) respectively. Find the velocity and displacement of particle at t = 2s.

Velocity and accleration of a [article at time t=0 are vecu=(2hati+3hatj) m/s and veca=(4hati+2hatj)m//s^(2) respectively. Find the velocity and dispalcement of the particle at t-2s.

Acceleration of a particle in x-y plane varies with time as a=(2t hati+3t^2 hatj) m//s^2 At time t =0, velocity of particle is 2 m//s along positive x direction and particle starts from origin. Find velocity and coordinates of particle at t=1s.

Acceleration of a particle in x-y plane varies with time as a=(2t hati+3t^2 hatj) m//s^2 At time t =0, velocity of particle is 2 m//s along positive x direction and particle starts from origin. Find velocity and coordinates of particle at t=1s.