[" An equilateral triangle "ABC" is inscribed in a circle.P is any point on the minor are BC.Prove "],[" that "PA=PB+PC]

The equilateral triangle ABC is inscribed in a circle. If P is any point on the ar BC, then prove that AB=PB+PC .

An equilateral triangle ABC is inscribed in a circle of radius r if P be any point on the circle then find the value of PA^(2)+PB^(2)+PC^(2)

If ABC is an equilateral triangle inscribed in a circle and P be any point on the minor arc BC which does not coincide with B or C, then prove that PA is angle bisector of angleBPC .

If ABC is an equilateral triangle inscribed in a circle and P be any point on the minor arc BC which does not coincide with B or C, prove that PA is angle bisector of angleBPC.

If ABC is an equilateral triangle inscribed in a circle and P be any point on the minor arc BC which does not coincide with B or C, then prove that PA is angle bisector of angleBPC .

P is any point in the interior of a triangle ABC. Prove that : PA+PB lt AC +BC

P is any point in the interior of a triangle ABC. Prove that : PA+PB lt AC +BC

Equilateral Delta ABC is inscribed in a circle with centre P. Then, angleBPC = ..........