A circle is concentric with circle `x^2+y^2-2x+4y-20=0` . If perimeter of the semicircle is 36 then the equation of the circle is: `[u s epi=22//7]` `x^2+y^2-2x+4y-44=0` `(x-1)^2+(y+2)^2=(126//11)^2` `x^2+y^2-2x+4y-43=0` `x^2=y^2-2x+4y-49=0`

A circle is concentric with circle x^(2)+y^(2)-2x+4y-20=0. If perimeter of the semicircle is 36 then the equation of the circle is: [use pi=22/7]x^(2)+y^(2)-2x+4y-44=0(x-1)^(2)+(y+2)^(2)=(126/11)^(2)x^(2)+y^(2)+(y+2y-43=0x^(2)=y^(2)-2x+4y-49=0

Circles x^2+y^2-2x-4y=0 and x^2+y^2-8y-4=0

Equation of unit circle concentric with circle x^(2)+y^(2)+8x+4y-8=0 is

The equation of the circle concentric with the circle x^2+y^2+8x+10y-7=0 and passing through the centre of the circle x^2+y^2-4x-6y=0 is

Equation of the circles concentric with the circle x^(2)+y^(2)-2x-4y=0 and touching the circle x^(2)+y^(2)+ 2x=1 must be-

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is a. x^(2)+y^(2)+2x-2y-62=0 b. x^(2)+y^(2)+2x-2y-47=0 c. x^(2)+y^(2)-2x+2y-62=0 d. x^(2)+y^(2)-2x+2y-47=0

From a point R(5,8), two tangents RPandRQ are drawn to a given circle S=0 whose radius is 5. If the circumcenter of triangle PQR is (2,3), then the equation of the circle S=0 is x^(2)+y^(2)+2x+4y-10=0x^(2)+y^(2)+x+2y-10=0x^(2)+y^(2)-x+2y-20=0x^(2)+y^(2)+4x-6y-12=0

The equation of the tangent to the circle x^(2)+y^(2)-4x+4y-2=0 at (1,1) is