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If m and n are positive integers satisfy...

If `m` and `n` are positive integers satisfying `1+cos2theta+cos4theta+cos6theta+cos8theta+cos10theta=(cosmtheta.sinntheta)/sintheta` then `(m+n)` is equal to

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If m and n are positive integers satisfying 1+cos2 theta+cos4 theta+cos6 theta+cos8 theta+cos10 theta=(cos m theta*sin n theta)/(sin theta) then (m+n) is equal to

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cos 3theta+cos 5theta+cos 7theta+cos 9theta=4 cos theta cos 2theta cos 6theta .

(3+cos4 theta)cos2 theta=4(cos^(8)theta-sin^(8)theta)

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If : cos theta+sintheta=1, "then" : cos theta-sintheta

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