For the neutralisation of `1` mol of `H_(2)SO_(4)` with `2` mols of `NaOH` in dilute solutions the heat evolved is

1 mol of H_(2) SO_(4) in mixed with 2 mol of NaIH . The heat evolved will be

1 mol H_(2)SO_(4) will exactly neutralise :

100 mL of mixture of NaOH and Na_(2)SO_(4) is neutralised by 10 mL of 0.5 M H_(2) SO_(4) . Hence,the amount of NaOH in 100 mL solution is

Assertion : Enthalpy of neutralisation of 1 equivalent each of HCl and H_(2)SO_(4) with NaOH is same Reason : Enthalpy of neutralisation is always the heat evolved when 1 mole acid is neutralised by a base.

A: Enthalpy of neutralisation of 1 equivalent each of HCl and H_(2)SO_(4) with NaOH is same. R : Enthalpy of neutralisation is always the heat evolved when 1 mole acid is neutralised by a base.

A: Enthalpy of neutralisation of 1 equivalent each of HCI and H_(2)SO_(4) with NaOh is same. R : Enthalpy of neutralisation is always the heat evolved when 1 mole acis is neutralised by a base.