The focal chord of the parabola `y^(2)=4ax` makes an angle `theta` with its aixs. Show that the length of the chord will be `4acosec^(2)theta`.

If the normal chord of the parabola y^(2)=4x makes an angle 45^(@) with the axis of the parabola, then its length, is

If the normal chord of the parabola y^(2)=4x makes an angle 45^(@) with the axis of the parabola, then its length, is

The length of a focal chord of the parabola y^(2)=4ax making an angle theta with the axis of the parabola is (a>0) is:

The normal chord of the parabola y^(2)=4ax subtends a right angle at the vertex.Then the length of chord is

If the normal chord of the parabola y^(2)=4 x makes an angle 45^(@) with the axis of the parabola, then its length, is

The length of a focal chord of the parabola y^2=4ax making an angle theta with the axis of the parabola is (a> 0) is :

If a normal chord of the parabola y^(2)=4x makes an angle of 45^(@) with the axis of the parabola then its length is

A focal chord of the Parabola y^(2) = 4x makes an angle of measure theta with the positive direction of the X - axis . If the length of the focal chord is 8 then theta = . . . . ( 0 lt theta lt (pi)/(2))

If a chord of the parabola y^(2)=4x passes through its focus and makes an angle theta with the X-axis then its length is