AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

AB and CD are equal chords of a circle whose centre is O,when produced these chords meet at E,Prove that EB=ED

In the given figure, AB and CD are the parallel chords of a circle with centre O. Such that AB = 8 cm and CD = 6 cm. If OMbotAB and OLbotCD distance becween LM is 7 cm. Find the radius of the circle ?

AD and AC are two equal chords of a circle with centre O. AB is the diameter of the circle. If angleCOD =140^@ , then angleOBC =

AB and CD are two equal and parallel chords in a circle.If the distance from the centre of the circle to the chord AB=2x units,then the distance between the chords is:

AB and CD are two chords of equal lengths of the circle with centre at O. The distance of the chord AB from the centre O is 4cm. Then the distance of the chords CD from the centre O is

AB and CD are chords of a circle with centre O. AB = 48 cm and its distance from centre O is 10 cm. If the distance of CD from centre O is 24 cm, find the length of CD.

In the given figure,AB and AC are two equal chords of a circle with centre O.Show that o lies on the bisectors of /_BAC.

Two equal chords AB and CD of a circle with centre O, intersect each other at E. Prove that AD = CB