`If sin theta = k sin (theta + phi),"show that", tan(theta + phi) = (sin phi)/(cos phi -k).`

If : sin (theta + phi) = 2 sin (theta - phi), "then" : tan theta = A) tan phi B) 2 tan phi C) 3 tan phi D) 4 tan phi

If sin theta=5sin(theta+phi) then tan(theta+phi)=

If cos theta+cos phi=a and sin theta - sin phi=b , then: 2cos(theta + phi) =

If " " tan theta = 1/7 " and " tan phi = 1/3 " show that", cos 2 theta = sin 4phi

If sintheta=5sin(theta+phi) then tan(theta+phi)=

The value of ((sin theta + sin phi)/(cos theta + cos phi)+ (cos theta - cos phi)/(sin theta - sin phi)) is :

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi),(cos phi sin phi,sin^2 phi)]=0

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi),(cos phi sin phi,sin^2 phi)]=0

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi), (cos phi sin phi,sin^2 phi)]=0

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi),(cos phi sin phi,sin^2 phi)]=0