`(1)/(5)log_(2) 32 + 3log_(64) 4` = ______.

(log_(3)729+log_(6)216)/(4+log_(2)16-2log_(4)64) = ______

The value of (1)/(5) log_(10) 3125 -4 log_(10)2 +log_(10)32 is

Evaluate : (i) log_(125) 625 - log_(16) 64 (ii) log_(16) 32 - log_(25) 125 + log_(9) 27 .

log_(2)1. log_(3)2. log_4)3.log_(5)4.log_(6)5……. Log_(200)199 = ______

Find x, if : (i) log_(3) x = 0 (ii) log_(x) 2 = -1 (iii) log_(9) 243 = x (iv) log_(5) (x - 7) = 1 (v) log_(4) 32 = x - 4 (vi) log_(7) (2x^(2) - 1) = 2

Find x, if : (i) log_(2) x = -2 (ii) log_(4) (x + 3) = 2 (iii) log_(x) 64 = (3)/(2)

if log_(64) P^(2)= 1""2/3 "then" log_(2) p/16 = ______

1+(1)/(3.2^(2))+(1)/(5.2^(4))+(1)/(7.2^(6))+.... (1)log_(e)2 (2)log_(e)3 (3)log_(e)4 (4)log_(e)5

(1)/(3)log_(10)125-2log_(10)4+log_(10)32

log_(x)4+log_(x)16+log_(x)64=12