[" 20.Let "1={x in R;x!=0,-4<=x<=4}" and "f:A rarr R" is defined by "f(x)=(|x|)/(x)" for "x in A" .Thenthe range "],[" of "f" is "]

Let A={x in R : x!=0,\ -4lt=xlt=4} and f: A->R be defined by f(x)=(|x|)/x for x in Adot Then \ f is a. {-1, 1} b. (3//4,1] c. [3//4,1] d. (3//4,1)

Let A={x in R : x ne 0, -4le xle4} and f:A rarrR is defined by f(x)=(|x|)/(x) for x in A. Then the range of f is

Let A={x in R :-4lt=xlt=4 and x!=0} and f: A->R be defined by f(x)=(|x|)/x . Write the range of fdot

Let A={x in R :-4lt=xlt=4 and x!=0} and f: A->R be defined by f(x)=(|x|)/x . Write the range of fdot

Let A={x in R : |x+1| = |x|+1} and B ={x in R : |x-1| = |x|-1} , Then

Let A = {1, 2, 3, 4}, B = {1, 3, 4, 8}. Let R = {x, y) : x in A, y in B and x divides y}. Write R in roster form.

Let A = {1, 2, 3, 4}, B = {1, 3, 4, 8}. Let R = {x, y) : x in A, y in B and x divides y}. Write R in roster form.

Let f:R to R be a function such that |f(x)|le x^(2),"for all" x in R. then at x=0, f is

Let f_1:R→R,f_2:[0,∞)→R, f_3:R→R and f_4:R→[0,∞) be defined by f_1(x)={ ∣x∣ if x<0 ; e^x if x≥0 ; f_2(x)=x^2 ; f_3(x)={ sin x if x<0 ; x if x≥0 ; f_4(x)={ f_2(f_1(x)) if x<0 f_2(f_1(x)) if x≥0 ​then f_4 is