(2sin(A-c)cos-sin(A-2c))/(2sin(B-c)cos c-sin(B-2)phi)=(sin A)/(sin B)

(2sin (AC) cos C-sin (A-2C)) / (2sin (BC) cos C-sin (B-2C)) = (sin A) / (sin B)

(2sin (AC) cos C-sin (A-2C)) / (2sin (BC) cos C-sin (B-2C)) = (sin A) / (sin B)

Prove that: (sin(A-C)+2sin A+sin(A+C))/(sin(B-C)+2sin B+sin(B+C))=(sin A)/(sin B)

In /_ABC if cos A cos B+sin A sin B sin C=1, then the value of (sin^(2)A)/(sin^(2)B)+2(sin^(2)B)/(sin^(2)C)+(sin^(2)C)/(sin^(2)A) is equal to

sin ^ (2) A + sin ^ (2) B-sin ^ (2) C = 2sin A sin B cos C

In any triangle ABC,sin^(2)A-sin^(2)B+sin^(2)C is always equal to (A) 2sin A sin B cos C(B)2sin A cos B sin C(C)2sin A cos B cos C(D)2sin A sin B sin C

(cos A)/(sin B sin C)+(cos B)/(sin C sin A)+(cos C)/(sin A sin B)=2

If : A+B+C= pi "then" : 1 - sin^(2)""(A)/(2) - sin^(2)""(B)/(2)+ sin^(2)""(C)/(2)= A) 2cos""(A)/(2) * cos sin ^(2)""(B)/(2) + sin^(2)""(C)/(2) B) 2 cos ""(B)/(2)* cos ""(B)/(2) * sin""(C)/(2) C) 2 cos ""(C)/(2)* cos ""(A)/(2) * sin""(B)/(2) D) 2 cos ""(A)/(2)* cos ""(B)/(2) * sin""(C)/(2)