`(na (1+alog x)^(n-1))/(x(l+a logx)^(n))` का समाकलन कीजिये -

int((logx)^n)/(x)dx=

d/dx(x^n.logx)

Write a value of int1/(x\ (logx)^n)\ dx

int x^n logx dx

If I_(m,n) - int (x^(m) (logx)^(n) dx then I_(m,n) - (x^(m+1))/((m + 1)) (logx)^(n) =

If I_(n) = int(logx)^(n) dx then prove that I_(n) = x(logx)^(n) - nI_(n-1) and hence evaluate int(log x)^(4) dx

(d^n)/(dx^n)(logx)= ((n-1)!)/(x^n) (b) (n !)/(x^n) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)

(d^n)/(dx^n)(logx)=? (a) ((n-1)!)/(x^n) (b) (n !)/(x^n) (c) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)

(d^n)/(dx^n)(logx)= (a) ((n-1)!)/(x^n) (b) (n !)/(x^n) (c) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)

(d^n)/(dx^n)(logx)=? (a) ((n-1)!)/(x^n) (b) (n !)/(x^n) (c) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)