" 2."cos theta-cos2 theta=sin3 theta

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

Prove that : (2 cos^(3) theta-cos theta)/(sin theta-2 sin^(3)theta)=cot theta

Prove that : (2 cos^(3) theta-cos theta)/(sin theta-2 sin^(3)theta)=cot theta

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

If sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha, then theta is equal to

sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha then theta is equal to

(cos3 theta+2cos5 theta+cos7 theta)/(cos theta+2cos3 theta+cos5 theta)=cos2 theta-sin2 theta tan3 theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

(cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta

Prove that : (cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta