100 mL of `NaHC_(2)O_(4)` required 50 mL of 0.1M `KMnO_(4)` solution in acidic medium. Volume of 0.1M NaOH required by 100 mL of `NaHC_(2)O_(4)` is :

Aqueous solutions of Na_(2)C_(2)O_(4) and CaCI_(2) are mixed and precipitate of CaC_(2)O_(4) formed is filered and dried. 250 mL of the saturated solution of CaC_(2)O_(4) required 6.0 mL of 0.001M KMnO_(4) solution in acidic medium for complete titration. Equivalent of KMNO_(4) required in the titration and equivalent of C_(2)O_(4)^(2-) ion present in CaC_(2)O_(4) , respectively, are

Aqueous solutions of Na_(2)C_(2)O_(4) and CaCI_(2) are mixed and precipitate of CaC_(2)O_(4) formed is filered and dried. 250 mL of the saturated solution of CaC_(2)O_(4) required 6.0 mL of 0.001M KMnO_(4) solution in acidic medium for complete titration. Equivalent of KMNO_(4) required in the titration and equivalent of C_(2)O_(4)^(2-) ion present in CaC_(2)O_(4) , respectively, are

100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium ( MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium ( MnO_(4)^(-) reduced to MnO_(2) ). Find the value of v:

100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium ( MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium ( MnO_(4)^(-) reduced to MnO_(2) ). Find the value of v:

The amount of KMnO_(4) required to prepare 100mL of a 0.1N solution in an acidic medium is :

X gm of KHC_(2)O_(4) requires 100 ml of 0.02 M KMnO_(4) in acidic medium. In another experiment, y gm of KHC_(2)O_(4) requires 100 mkl of 0.05 M Ca(OH)_(2) . The ratio of x and y is

X gm of KHC_(2)O_(4) requires 100 ml of 0.02 M KMnO_(4) in acidic medium. In another experiment, y gm of KHC_(2)O_(4) requires 100 mkl of 0.05 M Ca(OH)_(2) . The ratio of x and y is

20 ml of 0.1 M FeC_(2)O_(4) solution is titrated with 0.1 M KMnO_(4) is acidic medium. Volume of KMnO_(4) solution required to oxidise FeC_(2)O_(4) completely is