The position of a particle moving along x- axis is given by `x=x_0 cos^2(omegat)` . Its when it is at mean position is

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

The position x of particle moving along x-axis varies with time t as x=Asin(omegat) where A and omega are positive constants. The acceleration a of particle varies with its position (x) as

The position x of particle moving along x-axis varies with time t as x=Asin(omegat) where A and omega are positive constants. The acceleration a of particle varies with its position (x) as

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

The potential energy U(x) of a particle moving along x - axis is given by U(x)=ax-bx^(2) . Find the equilibrium position of particle.

The potential energy U(x) of a particle moving along x - axis is given by U(x)=ax-bx^(2) . Find the equilibrium position of particle.