A charged particle having charge q and mass m moves rectilinearly under the action of the electric field `E(x)=(4-3x)N//C` where x is the distance was initially at rest. The distance travelled by the particle till it comes instantaneously to rest again for the first time, is

A particle of charge q and mass m moves along the x-axis under the action of an electric field E=k-cx , where 'c' is a positive constant and x is the distance from the point, where the particle was initially at rest. Calculate: (a) distance travelled by the particle before it comes to rest. (b) acceleration at the moment, when it comes to rest.

A particle with specific charge q//m moves rectilinerarly due to an electric field E = E_(0) - ax , where a is a positive constant, x is the distance from the point where the particle was initially at rest. Find: (a) the distance covered by the particle till the moment it came to a standstill, (b) the acceleration of the particle at that moment.

A particle of charge q and mass m is prjected in a uniform and contant magnetic field of strength B .The initial velocity vecv makes angle theta with the vecB .Find the distance travelled by the particle in time t .

The distance travelled by a particle starting from rest and moving with an acceleration 4/3m/s2 ,in the third-second is

Charged particle of charge q mass m moves in a circular path of radius r under the action of force F .The equivalent current is

Charged particle of charge q mass m moves in a circular path of radius r under the action of force F .The equivalent current is

A particle is moving along the x-axis whose acceleration is given by a= 3x-4 , where x is the location of the particle. At t = 0, the particle is at rest at x = 4//3m . The distance travelled by the particles in 5 s is

A particle start moving from rest state along a straight line under the action of a constant force and travel distance x in first 5 seconds. The distance travelled by it in next five seconds will be