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A small body of mass m is suspended wit...

A small body of mass m is suspended with the help of light cord of force constant K=`(2mg)/(l)` .Initially block is at rest and the extension in the cord is `(l)/(2)` .Now, it is displaced downward from equilibrium by distance `l` and released.(neglect energy loss in cord). Find the time period of oscillation.If your answer is `x sqrt((l)/(g))`,report the value of x rounded to two decimals.

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