P and Q are two variable points on the axes of x and y respectively such that |OP| + |OQ|=a, then the locus of foot of perpendicular from origin on PQ is

Let coordinates of the points A and B are (5, 0 ) and (0, 7) respectively. P and Q are the variable points lying on the x- and y-axis respectively so that PQ is always perpendicular to the line AB. Then locus of the point of intersection of BP and AQ is

P is a point on the parabola y^(2)=4ax whose ordinate is equal to its abscissa and PQ is focal chord, R and S are the feet of the perpendiculars from P and Q respectively on the tangent at the vertex, T is the foot of the perpendicular from Q to PR, area of the triangle PTQ is

A variable plane makes intercepts on X, Y and Z-axes and it makes a tetrahedron of volume 64cu. Units. The locus of foot of perpendicular from origin on this plane is

A variable line makes intercepts on the coordinate axes the sum of whose squares is constant and is equal to a.Find the locus of the foot of the perpendicular from the origin to this line.

Tangents are drawn to y^(2)=4ax from a variable point P moving on x+a=0 ,then the locus of foot of perpendicular drawn from P on the chord of contact of P is

A variable straight line passes through a fixed point (h,k). Find the locus of the foot of the perpendicular on it drawn from the origin.

P is any point on the x-a=0. If A=(a,0)and PQ , the bisector of angleOCA meets the x-axis in Q prove that the locus of the foot of prependicular from Q on Op is (x-a)^2(x^2+y^2)=a^2y^2