Consider the curve `y=ce^((x)/(a))` the equation of normal to the curve where the curve cut `y` -axis is

Consider the curve y=ce^(x/a ) .The equation of normal to the curve when the curve cut y-axis is

The equation of normal to the curve y^(2)=8x is

The equation of normal to the curve y=2cosx at x=pi/4 is

The equation of normal to the curve y^(2) = 8x at (1,2) is :

The equation of normal to the curve sqrt(x)-sqrt(y)=1 at (9,4) is

In the curve y=ce^((x)/(a)), the sub-tangent is constant sub-normal varies as the square of the ordinate tangent at (x_(1),y_(1)) on the curve intersects the x-axis at a distance of (x_(1)-a) from the origin equation of the normal at the point where the curve cuts y-axis is cy+ax=c^(2)

Equation of normal to curve y=b*e^(-(x)/(a)) where it cuts the y-axis,is

Equation of normal to the curve y=ax^(3)+bx^(2)+c , where the curve crosses the Y-axis, is

The equation of the normal to the curve y=x^(-x) at the point of its maximum is

The equation of normal to the curve x^(2)=3-2y at (1,1) is :