As shown in Fig, a dielectric material of dielectric constant K is insered in half portan between plates of parallel plate capacitor. If its initial capacitance is C, what is the new capacitance ?

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

A parallel plate capacitor is filled with dielectrics as shown in Fig. What is its capacitance ?

If a dielectric slab of thickness 5 mm and dielectric constant K=6 is introduced between the plates of a parallel plate air capacitor, with plate separation of 8 mm, then its capacitance is

A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor, but has a thickness 3d//4 . Find the ratio of the capacitanace with dielectric inside it to its capacitance without the dielectric.

For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area is the plates of the capacitor. The thick of the directrie slab is (3)/(4)d, where ‘d’ is the separation between the plates of parallel plate capacite. The new capacitance (C') in terms of original capacitance (C _(0)) is given by the following relation:

Two dielectric slabs of constant K1 and K2 have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor