Home
Class 12
PHYSICS
As shown in the figure an insulating mat...

As shown in the figure an insulating material of dielectric constant K is inserted into half of the space between the plates. If initial capacitance of the capacitor was C, then its new capacitance will be

Promotional Banner

Similar Questions

Explore conceptually related problems

As shown in Fig, a dielectric material of dielectric constant K is insered in half portan between plates of parallel plate capacitor. If its initial capacitance is C, what is the new capacitance ?

When dielectric is inserted in the space between plates of a capacitor, then

parallel plate capacitor has capacitance C when no dielectric between thw plates. Now a slab of dielectric constant K , having same thickness as the separation between the plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. the new capacitance will be

Two capacitors of capacitance C and nC are connected in parallel. A battery of emf V is connected across the combination. Now the battery is removed and a dielectric constant K is inserted filling the space between the plates of capacitor of capacitance C. The final potential difference across the system is

A parallel plate capacitor with vacuum between its plates has capacitance C . A slabe of dielectric constant K and having the same thickness as the separation between the plates is introduced so as to fill 1//3^(rd) of the capacitor as shown in the figure. the new capacitance will be

A parallel plate capacitor with air as the dielectric has capacitance C. A slab of dielectric constant K and having the same thickness as the separation between plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be :

A metal plate of thickness half the separation between the capacitor plates of capacitance C is inserted. The new capacitance is.

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance