A body starts from rest and moves with uniform acceleration. What is the ratio of kinetic energies at the end of `1st , 2nd` and `3rd` seconds of its journey ?

A body starts from rest and then moves with uniform acceleration. Then.

A body starts from rest and moves with constant acceleration. The ratio of distance covered by the body in nth second to that covered in n second is.

A body starts from rest with a uniform acceleration ‘a'. Find the distance covered by the body in nth second.

A bus starts from rest and moves whith acceleration a = 2 m/s^2 . The ratio of the distance covered in 6^(th) second to that covered in 6 seconds is

A body starting from rest moves with constant acceleration. What is the ratio of distance covered by the body during the fifth second of time to that covered in the first 5.00 s ?

A body starts from rest with uniform acceleration. The velocity of the body after t seconds is v. The displacement of the body in last three seconds is

Starting from rest, when a body moves with uniform acceleration, then distances covered after 1st, 2nd, 3rd, ... seconds are in the ratio

A body starts from rest and moves for n seconds with uniform acceleration a, its velocity after n seconds is v. The displacement of the body in last 3 seconds is :