The range of a random variable x is (0,1,2) .Given that `p(x=2)=3c^(3), p(x=1)=4c-10c^(2), p(x=2)=5c-1` where c is constant .Find i) the value of `C` (ii) `p(xlt1)` iii) `p(1lexlt2)` iv) `p(0ltxle3)`

A random variable x has its range {0,1,2} and the probabilities are given by P(x=0) =3k^(3), P(x=1) =4k-10k^(2) , P(x=2) =5k-1 where k is a constant then k=

The range of a random variable X is 1,2,3,..., and P(X=k)=(c^(k))/(k!) where k=1,2,3... .Find the value of P(0ltXlt3)

The probability distribution function of a random variable X is given by x_i :012 p_i :3c^34c-10 c^25c-1 Where c >0 Find : (i) c (ii) P(X<2) (ii) P(1

The probability distribution of a random variable x is given as under P(X=x)={{:(kx^(2),x="1,2,3"),(2kx,x="4,5,6"),("0,","otherwise"):} where, k is a constant. Calculate (i) E(X) (ii) E(3X^(2)) (iii) P(Xge4)

The random variable X can the values 0,1,2,3, Give P(X=0)=P(X=1)=p and P(X=2)=P(X=3) such that sum p_(i)x_(i)^(2)=2sum p_(i)x_(i) then find the value of p

The p.m.f. of a r.v. X is as follows : P(X=0)=3k^(3),P(X=1)=4k-10k^(2),P(X=2)=5k-1 , P(X=x)=0" for any other values of x, then "P(Xlt1) =

Cosider the function f(x)=|{:(x^(3),sin x,cos x),(6,-1,0),(p,p^(2),p^(3)):}| , where p is a constant. What is the value of p for which f''(0) = 0 ?

The range of random variable X={1,2,3,....oo} and the probabilities are given by P(x=k)=(C^(k))/(|__k) . Then C=

A random variable X has its range (1 2 3} If P(X=1)=alpha P(X=2)=beta, p(X=3)=(1)/(6) and the mean is (5)/(3) then alpha , beta=

The random variable X can take only the values 0;1;2. Giventhat P(X=0)=P(X=1)=p and that E(X^(2))=E(X); find the value of p.