The electric field on two sides of a thin sheet of charge is shown in the figure. The charge density on the sheet is

The electric field on two sides of a large charged plate is shown in figure. The charge density on the plate in SI units is given by (epsilon_0 is the permittivity of free space in SI units).

A charged ball B hangs from a silk thread S , which makes an angle theta with a large charged conducting sheet P , as shown in the figure. The surface charge density sigma of the sheet is proportional to

A charged ball B hangs from a silk thread S, which makes an angle theta with a large charged conducting sheet P, as shown in figure. The surface charge density sigma of the sheet is proportional to

Why do we always get electric field intensity near a charged metallic surface of magnitude twice of the electric field intensity near a thin sheet of charge with same surface charge density as of metal plate?

The electric field at a point near an infinite thin sheet of a charged conductor is .

Electric field intensity at a point due to an infinite sheet of charge having surface charge density sigma is E .If sheet were conducting electric intensity would be

a)State Gauss’s law in electrostatics. Show that with help of suitable figure that outward flux due to a point charge Q, in vacuum within gaussian surface, is independent of its size and shape. b) In the figure there are three infinite long thin sheets having surface charge density +2sigma, -2sigma and +sigma respectively. Give the magnitude and direction of electric field at a point to the left of sheet of charge density +2sigma and to the right of sheet of charge density +sigma

A large charged metal sheet is placed in a uniform electric field, perpendicular to the electric field lines. After placing the sheet into the field, the electric field on the left side of the sheet is E_1 = 5 xx 10^5 Vm^(-1) and on the right it is E_2 = 3 xx 10^5 V m^(-1) . The sheet experiences a net electric force of 0.08 N. Find the area of one face of the sheet. Assume the external field to remain constant after introducing the large sheet. Use (1/(4piepsilon_0)) = 9 xx 10^(9) Nm^(2)C^(-2)

A charged large metal sheet is placed into uniform electric field, perpendicularly to the electric field lines. After placing the sheet into the field, the electric field on the left side of the sheet is E_(1)=5xx10^(5)V//m and on the right it is E_(2) = 3xx10^(5)V//m . The sheet experiences a net electric force of 0.08N. Find the area of one face of the sheet. Assume external field to remain constant after introducing the large sheet. Use (1/(4pivarepsilon_(0)))=9xx10^(9)Nm^(2)//C^(2)