If 6,10,14 are the sides of a triangle then it's obtuse angle is

Can a triangle have two obtuse angles? Why?

If the roots of the equation c^(2)x^(2)- c(a+b)x + ab =0 are sin A, sin B where A, B and C are the angles and a, b, c are the opposite sides of a triangle, then the triangle is : (i) right angled (ii) acute angled (iii) obtuse angled (iv) sin A + cos A = (a+b)/(c )

By giving a counter-example, show that the following statement is false: p: If all the sides of a triangle are equal, then the triangle is obtuse angled.

If ax^(2)+bx+c=0 and 5x^(2)+6x+12=0 have a common root where a, b and c are sides of a triangle ABC , then (A) Delta ABC is obtuse angled (B) Delta ABC is acute angled (C) Delta ABC is right angled (D) no such triangle exists

Write the sum of the angles of an obtuse triangle.

A right triangle cannot have an obtuse angle.

If AB=(3,-2,2),BC=(-1,0,-2) sides of a parallelogram,then the obtuse angle between its diagonals is

If triangle ABC , is obtuse angled at C , then