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The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength 491 nm is 0.710 V. When the incident wavelength is changed to a new value, the stopping potential is 1.43 V. The new wavelength is :

Energy required to remove an electron from aluminium surface is 4.3 V. If light of wavelength 2000 Å falls on the surface, the velocity of the fastest electron ejected from the surface will be

The stopping potential for electrons emitted from a surface illuminated by light of wavelength 491 nm is 0.710 V. When the incident wavelength is changed to a new value, the stopping potential is 1.43 V. (a) What is this new wave- length? (b) What is the work function for the surface?

Express each of the following as a Roman numeral : (i) 2 (ii) 8 (iii) 14 (iv) 29 (v) 36 (vi) 43 (vii) 54 (viii) 61 (ix) 73 (x) 81 (xi) 91 (xii) 95 (xiii) 99 (xiv) 105 (xv) 114

Ag(s)|AgCI("saturated salt") KCI(C=0.025)||KNO_(3),AgNO_(3)(C=0.2)|Ag The emf of above cell is 0.43 V (a) write down the cell reactio (b) calculate the solubility product of AgCI

Common factor of (47^(43)+43^(43)) and (47^(47)+43^(47))

A common factor of (41^(43)+43^(43)) and (41^(41)+43^(41)) is ……