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((4i^3-i)/(2i+1))^2 can be expressed in ...

`((4i^3-i)/(2i+1))^2` can be expressed in `a+i b` as `3+4i` b. `3-4i` c. `4+3i` d. `4-3i`

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((4i^(3)-i)/(2i+1))^(2) can be expressed in a+ib as (A) 3+4i(B)3-4i(C)4+3i(D)4-3i

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