If `x=sin theta|sin theta|, y=cos theta|cos theta|,` where `99pi/2<=theta<=50pi,` then

If m=sin theta|sin theta| and n=cos theta|cos theta| and (99 pi)/(2)

If x=2sin theta-sin2 theta and y=2cos theta-cos2 theta , theta in[0,2 pi], then (d^(2)y)/(dx^(2)) at theta=pi is

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

If x=sin theta-theta cos theta , y=cos theta+theta sin theta then (d^(2)y)/dx ^2=

if x=sin theta+theta cos theta,y=cos theta-theta sin theta then ((dy)/(dx))_(theta=(pi)/(2))=

If x = theta cos theta + sin theta, y = cos theta- theta sin theta , then dy/dx at theta = pi/2

if A = [[cos theta, sin theta],[-sin theta, cos theta]] where theta = (2pi)/(7) then sum_(r=1)^(6) A^(r) =

Simplify, costheta[[cos theta, sin theta],[-sin theta, cos theta]] + sin theta [[sin theta, -cos theta],[cos theta, sin theta]]