(x+y)dy+(x-y)dx=0;y=1" when "x=1

For the given differential equation , find the particular solution satisfying the given condition: x^2dy+(x y+y^2)dx=0; y = 1 when x = 1

Find the particular solution of the differential equation satisfying the given conditions: x^2dy+(x y+y^2)dx=0; y=1\ when x=1.

Solve the differential equation (x+y)dy+(x-y)dx=0; given that y=1 when x=1.

Solve the differential equation x^2dy+(x y+y^2)dx=0 given y=1, when x=1

2 x y+y^2-2 x^2 (dy)/(dx)=0 , y=2 when x=1

(2x -2y+3) dx -(x-y+1) dy=0 , " when" x=0, y=1

Solve [xsin^2(y/x)-y]dx+x dy=0; y=pi/4 when x=1.

Solve [xsin^2(y/x)-y]dx+x dy=0; y=pi/4 when x=1.