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If the equation 2^x+4^y=2^y is solved fo...

If the equation `2^x+4^y=2^y` is solved for `y` in terms of `x` where `x<0,` then the sum of the solution is `x(log)_2(1-2^x)` (b) `x+(log)_2(1-2^x)` `(log)_2(1-2^x)` (d) `x(log)_2(2^x+1)`

A

`xlog_(2)(1-2^(x))`

B

`x+log_(2)(1-2^(x))`

C

`log_(2)(1-2^(x))`

D

`xlog_(2)(2^(x)+1)`

Text Solution

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The correct Answer is:
(b)
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DISHA PUBLICATION-LINEAR INEQUALITIES-Exercise -2 : Concept Applicator
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